Q: What does SPD F stand for and explain the Aufbau principle for writing electron configurations.
A: SPD F = the four subshell types: s (max 2 electrons), p (max 6), d (max 10), f (max 14). Mnemonic: Students Play During Free time. Aufbau principle: electrons fill lowest energy orbitals first. Fill order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p... Note: 4s fills BEFORE 3d but EMPTIES first when forming ions. Pauli exclusion principle: each orbital holds max 2 electrons with opposite spins. Hund's rule: within a subshell, electrons occupy separate orbitals before pairing (parallel spins). Exception: Cr ([Ar]3d⁵4s¹) and Cu ([Ar]3d¹⁰4s¹) — half-filled and fully-filled d subshells are extra stable.
Q: Explain the four main periodic trends and the direction of each.
A: Atomic radius: increases DOWN (more shells) and LEFT (fewer protons pulling electrons). Ionization energy (IE): energy to remove outermost electron. Increases UP and RIGHT — opposite of radius. More protons = electrons held more tightly. Electronegativity: tendency to attract bonding electrons. Increases UP and RIGHT. Fluorine is highest (4.0). Electron affinity: energy released when atom gains electron. Generally increases UP and RIGHT (with exceptions). Key relationship: as radius decreases, IE and electronegativity increase — all driven by the same factor: nuclear charge relative to electron shielding.
Q: Why do Chromium (Cr) and Copper (Cu) have unexpected electron configurations?
A: Expected: Cr = [Ar]3d⁴4s² and Cu = [Ar]3d⁹4s². Actual: Cr = [Ar]3d⁵4s¹ and Cu = [Ar]3d¹⁰4s¹. Reason: half-filled (d⁵) and fully-filled (d¹⁰) d subshells have extra stability due to exchange energy (electrons in separate orbitals with parallel spins lower the energy). One electron 'steals' from 4s to achieve this stability. Remember: Chrome Copper Cheat — they steal from 4s. This comes up on every general chemistry exam. Note: when transition metals form ions, 4s electrons are ALWAYS removed first — Fe²⁺ loses both 4s electrons before any 3d electrons.
Q: Name the 6 noble gases using the mnemonic and explain why they are unreactive.
A: He Never Argued; Krypton's Xenon Radon = Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn) — Group 18. They are unreactive because they have complete valence shells: He has 2 electrons (full 1s²), all others have 8 (ns²np⁶ configuration). No tendency to gain, lose, or share electrons. Exceptions: Xe and Kr can form compounds with highly electronegative F and O under extreme conditions (XeF2, XeF4, XeO3). Radon is radioactive. Uses: He in balloons/MRI cooling, Ne in signs, Ar in welding/light bulbs, Kr and Xe in specialty lighting.
Q: What is the significance of valence electrons and how do group numbers reveal them?
A: Valence electrons are the outermost electrons that participate in bonding — they determine an element's chemical behavior. Group number = number of valence electrons for main group (A) elements: Group 1 (IA) = 1 valence electron (alkali metals), Group 2 (IIA) = 2, Group 13 (IIIA) = 3... Group 17 (VIIA) = 7 (halogens), Group 18 (0/VIII) = 8 (noble gases, except He=2). Transition metals are more complex (d electrons involved). The mnemonic 'IA = I Am one valence electron' — Group 1A has 1. This is why elements in the same group have similar chemistry — same number of valence electrons = same bonding behavior.