📐 Calculus
u-sub: See f(g(x))·g'(x)? Let u = g(x)
U-Substitution — The most powerful basic integration technique
1
Recognize the pattern
U-substitution is essentially the chain rule run in reverse for integration. Look for an integral containing a composite function multiplied by the derivative of its inner function: ∫f(g(x))·g'(x)dx.
2
Choose u and find du
Let u equal the inner function g(x). Then du = g'(x)dx — the derivative of u with respect to x, times dx.
3
Replace everything and integrate
Substitute u for g(x) and du for g'(x)dx throughout the integral, leaving an integral purely in terms of u. Integrate this simpler expression.
4
Substitute back
Once you've integrated in terms of u, replace u with its original expression in x to give your final answer — don't leave the answer in terms of u.
1
Evaluate ∫2x·cos(x²)dx. Notice the pattern: cos(x²) is a composite function, and 2x is exactly the derivative of the inner function x².
2
Let u = x² (the inner function). Then du = 2x·dx (the derivative of the inner function, times dx) — which conveniently matches exactly what's left in the integral.
3
Substitute: the integral becomes ∫cos(u)du, which integrates to sin(u) + C.
4
Substitute back u = x²: the final answer is sin(x²) + C.

Exams test whether you can recognize when u-substitution applies (spotting a composite function multiplied by its inner derivative), correctly compute du, and remember to substitute back to the original variable at the end.

The most common trap is forgetting to substitute back to the original variable x at the end — leaving the final answer in terms of u is an incomplete answer, since the original integral was in terms of x.

1. What pattern signals that u-substitution should be used?
An integral containing a composite function multiplied by the derivative of its inner function: f(g(x))·g'(x).
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2. Evaluate ∫2x·cos(x²)dx using u-substitution.
sin(x²) + C.
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3. What is u-substitution essentially the reverse of?
The chain rule, run in reverse for integration.
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4. What is the final step of u-substitution that's often forgotten?
Substituting back from u to the original variable x.
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5. If u = x², what does du equal?
2x·dx.
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